Q42 / 107 · NTA Abhyas (JEE Main) 2020 · Physics · Oscillations

When a string is divided into three segments of lengths l1, l2 and l3 the fundamental frequencies of these three segments are ν1, ν2 and ν3 respectively. The original fundamental frequency ν of the string is

  • A
    ν=ν1+ν2+ν3
  • B
    ν=ν1+ν2+ν3
  • Correct answer
    C
    1ν=1ν1+1ν2+1ν3
  • D
    1ν=1ν1+1ν2+1ν3

Solution

Let l be the length of the string.

The fundamental frequency is given by

ν=12lT⁡μ

orν∝1l⁡ ( ∵ T and μ are constant )  

orν∝kl⁡ ( where k is a constant )

Here, l1=kν1, l2=kν2, l3=kν3 and l=kν

But l=l1+l2+l3

∴ 1ν=1ν1+1ν2+1ν3

Hence, the correct answer is option: 'C'.

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