When a mixture of 1-hexanol and hexanoic acid in diethyl ether is shaken with an aqueous $\mathrm{NaHCO}_3$ solution, then which of the following is right distribution?

• A

  In ether: hexanoic acid; In $\mathrm{NaHCO}_3$ : 1-hexanol
• Correct answer
  B

  In ether: 1-hexanol ; In $\mathrm{NaHCO}_3$ : sodium hexanoate
• C

  In ether: sodium hexaonate ; In $\mathrm{NaHCO}_3$ : 1hexanol
• D

  In ether: 1-hexanol ; In $\mathrm{NaHCO}_3$ : hexanoic acid

Solution

Hexanoic acid is soluble in ether whereas alcohol is not soluble in $\mathrm{NaHCO}_3$ solution.

Hence, the correct answer is option: 'B'.