When a metal conductor connected to left gap of a meter bridge is heated, the balancing point

We know that, resistance of unknown wire can be determined by using meter bridge as $$ \frac{R}{S}=\frac{l}{100-l} \Rightarrow S=\frac{R(100-l)}{l} $$ where $R=$ known resistance, $l=$ balancing length and $S=$ unknown resistance. When a metal conductor of resistance $R$ connected to left gap is heated, then its resistance increases i.e. $R$ increases. Hence, from Eq. (i), we see that when $R$ will increase, then $(100-l)$ will decrease also, i.e $l$ will increase. Therefore, balancing point will shift towards right.