Q14 / 200 · NEET 2004 · Botany

When a diploid female plant is crossed with a tetraploid male, the ploidy of endosperm cells in the resulting seed is:

  • Correct answer
    A
    tetraploidy
  • B
    pentaploidy
  • C
    diploidy
  • D
    triploidy.

Solution

Female parent genotype $=2 \mathrm{~N}=2 \mathrm{~A}$ Male Gamete formed $=\mathrm{N}=\mathrm{A}$ Male parent genotype $=2 \mathrm{~N}=4 \mathrm{~A}$ Male Gamete formed $=\mathrm{N}=2 \mathrm{~A}$ Endosperm is formed by the fusion of 2 polar nuclei (from female gamete) and 1 male gamete. Thus, the ploidy of endosperm $=$ $3 \mathrm{~N}=\mathrm{A}+\mathrm{A}+2 \mathrm{~A}=4 \mathrm{~A}$ (tetraploid)

Hence, the correct answer is option: 'A'.

Relevant Questions