Q60 / 160 · AP EAMCET 2020 (18 Sep Shift 2) · Mathematics

When a coin is tossed 6 times, the probability of getting more heads than tails is

  • A
    \(\frac{13}{32}\)
  • B
    \(\frac{15}{32}\)
  • C
    \(\frac{9}{32}\)
  • Correct answer
    D
    \(\frac{11}{32}\)

Solution

Total outcomes are \(2^6=64\) Required Probability \(=P\) (Getting Four Heads) \(+P\) (Getting 5 Heads) \(+P\) (Getting 6 Heads) \(=\frac{\frac{6 !}{4 ! 2 !}}{64}+\frac{\frac{6 !}{5 ! 1 !}}{64}+\frac{\frac{6 !}{6 !}}{64}=\frac{15}{64}+\frac{6}{64}+\frac{1}{64}=\frac{11}{32}\) Hence, option (d) is correct.

Hence, the correct answer is option: 'D'.

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