Q49 / 180 · COMEDK 2022 · Chemistry
What will be the density of $\text{N}_2$ gas at $230^\circ\text{C}$ and $3\text{ atm}$ pressure? ($R = 0.082\text{ L atm K}^{-1}\text{ mol}^{-1}$)
- A$3.41 \mathrm{~g} \prime \mathrm{L}$
- Correct answerB$2.03 \mathrm{~g} / \mathrm{L}$
- C$4.30 \mathrm{~g} / \mathrm{L}$
- D$0.27 \mathrm{~g} / \mathrm{L}$
Solution
$P = 3\,\text{atm}$, $T = 230 + 273 = 503\,\text{K}$, $M = 28\,\text{g/mol}$
$\rho = \dfrac{PM}{RT} = \dfrac{3 \times 28}{0.082 \times 503} = \dfrac{84}{41.246} \approx 2.03\,\text{g/L}$
Correct option: (2)
$\rho = \dfrac{PM}{RT} = \dfrac{3 \times 28}{0.082 \times 503} = \dfrac{84}{41.246} \approx 2.03\,\text{g/L}$
Correct option: (2)
Hence, the correct answer is option: 'B'.