What will be the current flowing through the $6 \mathrm{k} \Omega$ resistor in the circuit shown, where the breakdown voltage of the Zener is $6 \mathrm{V} ?$

• Correct answer
  A

  $\frac{2}{3} m A$
• B

  $1 \mathrm{mA}$
• C

  $10 \mathrm{mA}$
• D

  $\frac{3}{2} m A$

Solution

In the given circuit, the zener diode is used as a voltage regulating device. The voltage across $6 \mathrm{k} \Omega$ resistance is $(10-6) \mathrm{V}=4 \mathrm{V}$ Current through $6 \mathrm{k} \Omega$ resistor, $I=\frac{4 \mathrm{V}}{6 \mathrm{k} \Omega}=\frac{4}{6 \times 10^{3}}=\frac{2}{3} \times 10^{-3}=\frac{2}{3} \mathrm{mA}$

Hence, the correct answer is option: 'A'.