Q2 / 150 · MHT CET 2011 · Chemistry

What volume of $2 \mathrm{M} \mathrm{H}_{2} \mathrm{SO}_{4}$ is required to form $0.2 \mathrm{~N}$ of $100 \mathrm{~mL}$ of solution?

  • Correct answer
    A
    $5 \mathrm{~mL}$
  • B
    $20 \mathrm{~mL}$
  • C
    $10 \mathrm{~mL}$
  • D
    $50 \mathrm{~mL}$

Solution

$\because \mathrm{M}-\mathrm{H}_{2} \mathrm{SO}_{4}=2 \mathrm{~N}-\mathrm{H}_{2} \mathrm{SO}_{4}$ $\therefore 2 \mathrm{M}-\mathrm{H}_{2} \mathrm{SO}_{4}=4 \mathrm{~N}-\mathrm{H}_{2} \mathrm{SO}_{4}$ $N_{1} V_{1}=N_{2} V_{2}$ $4 \times V_{1}=0.2 \times 100$ $V_{1}=\frac{0.2 \times 100}{4}$ $=5 \mathrm{~mL}$

Hence, the correct answer is option: 'A'.

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