Q92 / 200 · JIPMER 2008 · Chemistry
What is \(X\) in the following nuclear reaction?
\({ }_7 \mathrm{~N}^{14}+{ }_1 \mathrm{H}^1 \longrightarrow{ }_8 \mathrm{O}^{15}+X\)
- A\({ }_0 n^1\)
- B\({ }_{-1} e^0\)
- C\({ }_{+1} e^0\)
- Correct answerD\(\gamma\)
Solution
\({ }_7 \mathrm{~N}^{14}+{ }_1 \mathrm{H}^1 \longrightarrow{ }_8 \mathrm{O}^{15}+ \gamma\)
Hence, the correct answer is option: 'D'.