Q26 / 150 · MHT CET 2026 (15 April Shift 1) · Chemistry
What is the value of the slope of a graph obtained by plotting the concentration of reactant $(A)_t$ versus time for zero order reaction?
- Correct answerA$-k$
- B$1/2k$
- C$k/2.303$
- D$2.303/k$
Solution
For a zero order reaction, the rate of reaction is independent of the concentration of the reactant.
The integrated rate equation for a zero order reaction is given by:
$[A]_t = -kt + [A]_0$
where $[A]_t$ is the concentration of the reactant at time $t$, $[A]_0$ is the initial concentration, and $k$ is the rate constant.
Comparing this equation with the equation of a straight line $y = mx + c$, we get:
$y = [A]_t$
$x = t$
$m = -k$
$c = [A]_0$
Thus, plotting the concentration of reactant $[A]_t$ versus time $t$ yields a straight line with a slope of $-k$.
Answer: $-k$
The integrated rate equation for a zero order reaction is given by:
$[A]_t = -kt + [A]_0$
where $[A]_t$ is the concentration of the reactant at time $t$, $[A]_0$ is the initial concentration, and $k$ is the rate constant.
Comparing this equation with the equation of a straight line $y = mx + c$, we get:
$y = [A]_t$
$x = t$
$m = -k$
$c = [A]_0$
Thus, plotting the concentration of reactant $[A]_t$ versus time $t$ yields a straight line with a slope of $-k$.
Answer: $-k$
Hence, the correct answer is option: 'A'.