Q35 / 170 · Manipal (MET) 2020 · Chemistry

What is the value of $x$ on the $\left[\mathrm{Ni}(\mathrm{CN})_4\right]^x$ complex ion?

  • A
    $+2$
  • Correct answer
    B
    $-2$
  • C
    0 (zero)
  • D
    $+4$

Solution

$\left.\left[\mathrm{Ni}(\mathrm{CN})_4\right)\right]^x \equiv\left[\mathrm{Ni}(\mathrm{CN})_4\right]^{2-}$ In this complex, the oxidation state of nickel is +2 and that of (CN) is - 1 . $\therefore \quad x=+2+y(-1)=-2$

Hence, the correct answer is option: 'B'.

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