Q196 / 270 · NDA 2016 (Phase 2) · Mathematics

What is the value of $\cos \left(2 \cos ^{-1}(0.8)\right.$ ?

  • A
    $0.81$
  • B
    $0.56$
  • C
    $0.48$
  • Correct answer
    D
    $0.28$

Solution

We know that $\begin{aligned} & 2 \cos ^{-1} x=\cos ^{-1} x\left(2 x^2-1\right) \\ & \text { here } x=0.8 \\ & \begin{aligned} \therefore \quad 2 \cos ^{-1}(0.8) & =\cos ^{-1}\left(2(0.8)^2-1\right) \\ & =\cos ^{-1}(0.28) \end{aligned} \end{aligned}$ Now, $\left(\cos ^{-1}(x)\right)=x$. $\therefore \cos \left(\cos ^{-1}(0.28)\right)=0.28$

Hence, the correct answer is option: 'D'.

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