What is the quantity of hydrogen gas liberated when 46 g sodium reacts with excess ethanol? (Given Atomic mass of Na = 23)

• A

  $2.4\times {10}^{-3}kg$
• Correct answer
  B

  $2.0\times {10}^{-3} kg$
• C

  $4.0\times {10}^{-3}kg$
• D

  $2.4\times {10}^{-2} kg$

Solution

1 mole of $H_2=2g$ of $H_2\equiv 2\times {10}^{-3} kg$

Hence, the correct answer is option: 'B'.