Q253 / 270 · NDA 2021 (Phase 2) · Mathematics

What is the probability that the roots of the equation $x^2+x+n=0$ are real, where $n \in \mathbb{N}$ and $n \lt 4$ ?

  • Correct answer
    A
    0
  • B
    $\frac{1}{4}$
  • C
    $\frac{1}{3}$
  • D
    $\frac{1}{2}$

Solution

A quadratic equation has only two roots. Here, $x^2+x+n=0$ and $n \in N$ where $n \lt 4$ $\therefore n=1,2,3 \Rightarrow$ Three equations are possible. Thus, Total number of Roots, $n=6$ $\rightarrow$ For equation $x^2+x+n=0 ; \mathrm{D}=1-4 n$ $\mathrm{D} \lt 0$ when $n=1,2$ and 3 $\therefore$ Equation will give complex roots not real. Thus, favourable number of roots, $r=0$ Hence, probability $=\frac{r}{n}=\frac{0}{6}=0$

Hence, the correct answer is option: 'A'.

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