Q20 / 150 · MHT CET 2024 (10 May Shift 1) · Chemistry

What is the oxidation number of carbon in $\mathrm{K}_2 \mathrm{C}_2 \mathrm{O}_4$ ?

  • A
    -2
  • B
    -3
  • Correct answer
    C
    +3
  • D
    +4

Solution

Let oxidation state of C be $x$ in $\mathrm{K}_2 \mathrm{C}_2 \mathrm{O}_4$. $\begin{array}{ll} & 2(+1)+2 x+4(-2)=0 \\ & 2+2 x-8=0 \\ & 2 x=6 \\ \therefore \quad & x=+3 \end{array}$

Hence, the correct answer is option: 'C'.

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