Q206 / 270 · NDA 2012 (Phase 1) · Mathematics

What is the number of ways that 4 boys and 3 girls can be seated so that boys and girls alternate?

A
12
B
72
C
120
Correct answer
D
144

Solution

B G B G B G B $4 \times 3 \times 3 \times 2 \times 2 \times 1 \times 1=144$

Hence, the correct answer is option: 'D'.

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