Q146 / 200 · MHT CET - Medical 2026 (25 April Shift 1) · Chemistry
What is the number of stereo structure of glucose?
- A$8$
- Correct answerB$16$
- C$32$
- D$64$
Solution
The open-chain structure of glucose is an aldohexose with the chemical formula $CHO-(CHOH)_4-CH_2OH$.
In this structure, there are $4$ chiral carbon atoms (the four $CHOH$ groups).
Since the molecule is unsymmetrical (the two terminal groups are different, $CHO$ and $CH_2OH$), the total number of stereoisomers is given by the formula $2^n$, where $n$ is the number of chiral centers.
Substituting $n = 4$, we get $2^4 = 16$.
Thus, there are $16$ possible stereo structures for an aldohexose like glucose.
Answer: $16$
In this structure, there are $4$ chiral carbon atoms (the four $CHOH$ groups).
Since the molecule is unsymmetrical (the two terminal groups are different, $CHO$ and $CH_2OH$), the total number of stereoisomers is given by the formula $2^n$, where $n$ is the number of chiral centers.
Substituting $n = 4$, we get $2^4 = 16$.
Thus, there are $16$ possible stereo structures for an aldohexose like glucose.
Answer: $16$
Hence, the correct answer is option: 'B'.