Q49 / 150 · MHT CET 2024 (11 May Shift 1) · Chemistry

What is the number of octahedral voids present in 0.2 mol of a compound forming hep structure?

  • Correct answer
    A
    $1.204 \times 10^{23}$
  • B
    $2.387 \times 10^{23}$
  • C
    $3.011 \times 10^{23}$
  • D
    $3.321 \times 10^{23}$

Solution

Number of atoms in 0.2 mol of the compound $=0.2 \times \mathrm{N}_{\mathrm{A}}=0.2 \times 6.022 \times 10^{23}$ $=1.2044 \times 10^{23}$ atoms a. Number of octahedral voids $\begin{aligned} & =\text { Number of atoms } \\ & =1.2044 \times 10^{23} \end{aligned}$

Hence, the correct answer is option: 'A'.

Relevant Questions