Q151 / 270 · NDA 2020 · Mathematics

What is the modulus of the complex number $\frac{\cos \theta+i \sin \theta}{\cos \theta-i \sin \theta}$, where $i=\sqrt{-1}$ ?

  • A
    $\frac{1}{2}$
  • Correct answer
    B
    1
  • C
    $\frac{3}{2}$
  • D
    2

Solution

$\text { } \begin{aligned} Z & =\frac{\cos \theta+i \sin \theta}{\cos \theta-i \sin \theta} \\ & =\frac{(\cos \theta+i \sin \theta)}{(\cos \theta-i \sin \theta)} \times \frac{(\cos \theta+i \sin \theta)}{(\cos \theta+i \sin \theta)} \\ & =\frac{(\cos \theta+i \sin \theta)^2}{\cos ^2 \theta-(i \sin \theta)^2} \\ & =\frac{\cos 2 \theta+i \sin 2 \theta}{\cos ^2 \theta+\sin ^2 \theta}=\cos 2 \theta+i \sin 2 \theta \end{aligned}$ Modulus of $Z=|Z|=\sqrt{\cos ^2(2 \theta)+\sin ^2(2 \theta)}=1$

Hence, the correct answer is option: 'B'.

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