Q151 / 270 · NDA 2020 · Mathematics
What is the modulus of the complex number $\frac{\cos \theta+i \sin \theta}{\cos \theta-i \sin \theta}$, where $i=\sqrt{-1}$ ?
- A$\frac{1}{2}$
- Correct answerB1
- C$\frac{3}{2}$
- D2
Solution
$\text { } \begin{aligned}
Z & =\frac{\cos \theta+i \sin \theta}{\cos \theta-i \sin \theta} \\
& =\frac{(\cos \theta+i \sin \theta)}{(\cos \theta-i \sin \theta)} \times \frac{(\cos \theta+i \sin \theta)}{(\cos \theta+i \sin \theta)} \\
& =\frac{(\cos \theta+i \sin \theta)^2}{\cos ^2 \theta-(i \sin \theta)^2} \\
& =\frac{\cos 2 \theta+i \sin 2 \theta}{\cos ^2 \theta+\sin ^2 \theta}=\cos 2 \theta+i \sin 2 \theta
\end{aligned}$
Modulus of $Z=|Z|=\sqrt{\cos ^2(2 \theta)+\sin ^2(2 \theta)}=1$
Hence, the correct answer is option: 'B'.