Q231 / 270 · NDA 2020 · Mathematics
What is the minimum value of $3 \cos \left(A+\frac{\pi}{3}\right)$ where $A \in R$ ?
- Correct answerA-3
- B-1
- C0
- D3
Solution
Let $y=3 \cdot \cos \left(A+\frac{\pi}{3}\right), y^{\prime}=-3 \cdot \sin \left(A+\frac{\pi}{3}\right)$
For extremum value, $y^{\prime}=0$
$\begin{aligned}
& \sin \left(A+\frac{\pi}{3}\right)=0 \Rightarrow A+\frac{\pi}{3}=0 \Rightarrow A=-\frac{\pi}{3} \\
& y^{\prime \prime}=-3 \cdot \cos \left(A+\frac{\pi}{3}\right) \\
& \quad=-3 \cos \left(-\frac{\pi}{3}+\frac{\pi}{3}\right)=-3 \cos (0)=-3
\end{aligned}$
Hence, the correct answer is option: 'A'.