Q168 / 270 · NDA 2014 (Phase 2) · Mathematics
What is the length of the latus rectum of the ellipse $25 x^2+16 y^2=400$ ?
- A$\frac{25}{2}$
- B$\frac{25}{4}$
- C$\frac{16}{5}$
- Correct answerD$\frac{32}{5}$
Solution
$\frac{25 x^2}{400}=\frac{16 y^2}{400}=\frac{400}{400} \Rightarrow \frac{x^2}{16}+\frac{y^2}{25} \quad=1$
Length of latus rectum of ellipse
$=\frac{2 a^2}{b}=\frac{2 \times 16}{5}=\frac{32}{5}$.
Hence, the correct answer is option: 'D'.