Q39 / 170 · Manipal (MET) 2019 · Chemistry

What is the general electronic configuration for 2nd row transition series?

  • A
    $[\mathrm{Ne}] 3 d^{1-10}, 4 s^2$
  • B
    $[\mathrm{Ar}] 3 d^{1-10}, 4 s^{1-2}$
  • Correct answer
    C
    $[\mathrm{Kr}] 4 d^{1-10}, 5 s^{1-2}$
  • D
    $[\mathrm{Xe}] 5 d^{1-10}, 5 s^{1-2}$

Solution

Transition elements have three series $3 d$, $4 d$ and 5d. $3 d$ series has elements $21(\mathrm{Sc})$ to $30(\mathrm{Zn})$ atomic number. 4 d series has elements 39 (Y) to 48 (Cd) atomic number. $[\mathrm{Kr}] 4 d^{1-10}, 5 s^{1-2}$ has IInd row series.

Hence, the correct answer is option: 'C'.

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