Q150 / 180 · KCET 2014 · Physics
What is the energy of the electron revolving in third orbit expressed in \( \mathrm{eV} \) ?
- Correct answerA\( 1.51 \mathrm{eV} \)
- B\( 3.4 \mathrm{eV} \)
- C(4.53 eV
- DO \( 4 \mathrm{eV} \)
Solution
We know that, energy of electron revolving in \( n^{\text {th }} \) orbit is given as
\( E_{n}=\frac{-13.6}{n^{2}} \)
For third orbit, \( n=3 \),
\( E_{3}=\frac{-13.6}{3^{2}}=\frac{-13.6}{9}=-1.5111 \mathrm{eV} \)
Therefore, energy of electron revolving in third orbit is \( 1.51 \mathrm{eV} \)
\( E_{n}=\frac{-13.6}{n^{2}} \)
For third orbit, \( n=3 \),
\( E_{3}=\frac{-13.6}{3^{2}}=\frac{-13.6}{9}=-1.5111 \mathrm{eV} \)
Therefore, energy of electron revolving in third orbit is \( 1.51 \mathrm{eV} \)
Hence, the correct answer is option: 'A'.