Q206 / 270 · NDA 2018 (Phase 2) · Mathematics

What is the distance of the point $(2,3,4)$ from the plane $3 \mathrm{x}-6 \mathrm{y}+2 \mathrm{z}+11=?$

  • Correct answer
    A
    1 unit
  • B
    2 unit
  • C
    3 unit
  • D
    4 unit

Solution

$\begin{aligned} \text { Distance } & =\left|\frac{3 \times 2-6 \times 3+2 \times 4+11}{\sqrt{3^2+(-6)^2+(2)^2}}\right| \\ & =\left|\frac{6-18+8+11}{\sqrt{49}}\right|=1\end{aligned}$

Hence, the correct answer is option: 'A'.

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