Q103 / 180 · AIIMS 2011 · Physics
What is the dimensions of magnetic field $B$ in terms of $\mathrm{C}$ (= coulomb), M, L, T?
- A$\left[\mathrm{M}^1 \mathrm{~L}^1 \mathrm{~T}^{-2} \mathrm{C}\right]$
- Correct answerB$\left[\mathrm{M}^1 \mathrm{~L}^0 \mathrm{~T}^{-1} \mathrm{C}^{-1}\right]$
- C$\left[\mathrm{M}^1 \mathrm{~L}^0 \mathrm{~T}^{-2} \mathrm{C}\right]$
- D$\left[\mathrm{M}^1 \mathrm{~L}^0 \mathrm{~T}^{-1} \mathrm{C}\right]$
Solution
$$
\begin{aligned}
& \text { }: B=\frac{F}{q v}=\frac{\left[\mathrm{MLT}^{-2}\right]}{[\mathrm{AT}]\left[\mathrm{LT}^{-1}\right]}=\left[\mathrm{ML}^0 \mathrm{~T}^{-2} \mathrm{~A}^{-1}\right] \\
& \text { But }[A]=\left[C \mathrm{~T}^{-1}\right] \\
& \therefore \quad[B]=\left[\mathrm{ML}^0 \mathrm{~T}^{-1} \mathrm{C}^{-1}\right]
\end{aligned}
$$
Hence, the correct answer is option: 'B'.