Q162 / 270 · NDA 2022 (Phase 2) · Mathematics
What is the diameter of a circle inscribed in a regular polygon of 12 sides, each of length 1 cm ?
- A$1+\sqrt{2} \mathrm{~cm}$
- B$2+\sqrt{2} \mathrm{~cm}$
- Correct answerC$2+\sqrt{3} \mathrm{~cm}$
- D$3+\sqrt{3} \mathrm{~cm}$
Solution
Central angle subtend by side $=\frac{360}{12}=30^{\circ}$

$\begin{aligned} & \tan 15^{\circ}=\frac{1 / 2}{r} \\ & \Rightarrow \frac{\sqrt{3}-1}{\sqrt{3}+1}=\frac{1}{2 r} \\ & \Rightarrow 2 r=\frac{\sqrt{3}+1}{\sqrt{3}-1}=\frac{4+2 \sqrt{3}}{2} \\ & \Rightarrow d=2+\sqrt{3} \mathrm{~cm}\end{aligned}$

$\begin{aligned} & \tan 15^{\circ}=\frac{1 / 2}{r} \\ & \Rightarrow \frac{\sqrt{3}-1}{\sqrt{3}+1}=\frac{1}{2 r} \\ & \Rightarrow 2 r=\frac{\sqrt{3}+1}{\sqrt{3}-1}=\frac{4+2 \sqrt{3}}{2} \\ & \Rightarrow d=2+\sqrt{3} \mathrm{~cm}\end{aligned}$
Hence, the correct answer is option: 'C'.