Q94 / 180 · NEET 2020 (Phase 2) · Physics

What is the depth at which the value of acceleration due to gravity becomes 1n, times the value at the surface of the earth? (radius of the earth =R)

  • A
    R n2
  • Correct answer
    B
    R(n-1)n
  • C
    Rn(n-1)
  • D
    Rn

Solution

The value of the acceleration due to gravity when the body moves below the surface of the earth at the depth, d in terms of the radius of the earth, and acceleration due to gravity at the surface of the earth, then at depth:

\(g_{\text {eff }}=g\left(1-\frac{d}{R}\right) \Rightarrow \frac{g}{n}=g\left(1-\frac{d}{R}\right) \Rightarrow d=\frac{(n-1) R}{n}\).

Hence, the correct answer is option: 'B'.

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