Q186 / 270 · NDA 2018 (Phase 2) · Mathematics
What is $\frac{2 \tan \theta}{1+\tan ^2 \theta}$ equal to?
- A$\cos 2 \theta$
- B$\tan 2 \theta$
- Correct answerC$\sin 2 \theta$
- D$\operatorname{cosec} 2 \theta$
Solution
$\begin{aligned} & \frac{2 \tan \theta}{1+\tan ^2 \theta}=\frac{2 \tan \theta}{\sec ^2 \theta} \\ & =2 \tan \theta \cdot \cos ^2 \theta \\ & =2 \sin \theta \cdot \cos \theta=\sin 2 \theta\end{aligned}$
Hence, the correct answer is option: 'C'.