Q33 / 150 · MHT CET 2021 (24 Sep Shift 1) · Chemistry
What is effective atomic number of $\mathrm{Pt} \operatorname{in}\left[\mathrm{Pt}\left(\mathrm{NH}_3\right)_4\right]^{2+}$ ? (Given atomic number of $\mathrm{Pt}=78$ )
- A76
- Correct answerB84
- C72
- D86
Solution
$$
\left[\mathrm{Pt}\left(\mathrm{NH}_3\right)_4\right]^{2+} \Rightarrow \mathrm{Pt}^{2+}
$$
\begin{array}{|l|l|l|l|l|l|}
\hline Complex & Metal & \begin{array}{l}\text { Atomic } \\
\text { number of } \\
\text { metal Z }\end{array} & \begin{array}{l}\text { Number of } \\
\text { electrons lost } \\
\text { by metal X }\end{array} & \begin{array}{l}\text { Number of } \\
\text { electrons } \\
\text { from } \\
\text { ligands Y }\end{array} & EAN = Z-X + Y \\
\hline\left[\mathrm{Pt}\left(\mathrm{NH}_3\right)_4\right]^{2+} & \mathrm{Pt} & 78 & 2 & 4 \times 2=8 & 78-2+8=84 \\
\hline
\end{array}
Hence, the correct answer is option: 'B'.