What are X and Y in the following set of reactions?

• A

  $\mathrm{X}=$ (i) DIBAL - H (ii) $\mathrm{H}_2 \mathrm{O}$ $\mathrm{Y}=$ (i) DIBAL - H (ii) $\mathrm{H}_2 \mathrm{O}$
• B

  $\mathrm{X}=\mathrm{H}_2 /$ Catalyst ; $\mathrm{Y}=\mathrm{H}_2$ / Catalyst
• Correct answer
  C

  $\mathrm{X}=\mathrm{H}_2$ / Catalyst ; $\mathrm{Y}=$ (i) DIBAL-H (ii) $\mathrm{H}_2 \mathrm{O}$
• D

  $\mathrm{X}=$ (i) DIBAL - H (ii) $\mathrm{H}_2 \mathrm{O} ; \mathrm{Y}=\mathrm{H}_2 /$ Catalyst

Hence, the correct answer is option: 'C'.