Q52 / 160 · JIPMER 2006 · Chemistry

What amount of $\mathrm{Cl}_2$ gas liberated at anode, if 1 ampere current is passed for 30 minute from NaCl solution?

  • A
    0.66 mol
  • B
    0.33 mol
  • Correct answer
    C
    0.66 g
  • D
    0.33 g

Solution

$2 \mathrm{Cl}^{-} \rightarrow \underset{1 \text { mole }}{\mathrm{Cl}_2}+\underset{2 \times 96500 \text { coulomb }}{2 e^{-} \text {(At anode) }}$ $\begin{aligned} Q & =i t=1 \times 30 \times 60 \\ & =1800 \text { coulomb }\end{aligned}$ The amount of chlorine liberated by passing 1800 coulomb of electric charge $=\frac{1 \times 1800 \times 71}{2 \times 96500}=0.66 \mathrm{~g}$

Hence, the correct answer is option: 'C'.

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