Q112 / 150 · MHT CET 2007 · Physics
We consider a thermodynamic system. If $\Delta U$ represents the increase in its internal energy and $W$ the work done by the system, which of the following statements is true?
- Correct answerA$\Delta U=-W$ is an adiabatic process
- B$\Delta U=W$ in an isothermal process
- C$\Delta U=-W$ in an isothermal process
- D$\Delta U=W$ in an adiabatic process
Solution
An isothermal process is a constant temperature process. In this process, $T=$ constant or $\Delta T=0$.
$$
\therefore \quad \Delta U=n C_{V} \Delta T=0
$$
An adiabatic process is defined as one with no heat transfer into or out of a system. Therefore, $Q=0 .$ From the first law of thermodynamics.
$W=-\Delta U$
or $\Delta U=-W$
Hence, the correct answer is option: 'A'.