Wavenumber for a radiation having 5800 Ã… wavelength is x × 10 ~cm^-1 . The value of x is ________ (Integer answer)

Correct answer: 1724. v( wave no. )=1/(λ)=frac15800 × 10^-8 ~cm=17241 OR 1724 × 10 ~cm^-1 ⇒ x=1724

Q21 / 90 · JEE Main 2024 (08 Apr Shift 2) · Chemistry

Wavenumber for a radiation having $5800 Ã…$ wavelength is $x \times 10 \mathrm{~cm}^{-1}$. The value of $x$ is ________ (Integer answer)

Correct answer: 1724

Solution

$\bar{v}($ wave no. $)=\frac{1}{\lambda}=\frac{1}{5800 \times 10^{-8} \mathrm{~cm}}=17241$ OR $1724 \times 10 \mathrm{~cm}^{-1} \Rightarrow \mathrm{x}=1724$

Hence, the correct answer is 1724.

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Wavenumber for a radiation having \(5800 Ã…\) wavelength is \(x \times 10 \mathrm{~cm}^{-1}\). The value of \(x\) is ________ (Integer answer)

Solution

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