Water is pumped steadily out of a flooded basement, at the speed of 10 m s^(-1) through a hose (tube) of radius, 1 cm, passing through a window, 3 m…

Question

Water is pumped steadily out of a flooded basement, at the speed of 10 m s^(-1) through a hose (tube) of radius, 1 cm, passing through a window, 3 m above the water level. The power of the pump is (Assume g=10 m s^(-2), density of water =1000 kg m^(-3))

MARKS Content Team · Accepted Answer

Correct answer: (B) 30π W. Power is defined as work-done per unit time, it means, P=W/t=mgh/t, from the equation of continuity, mass per unit time Avρ=m/t, ⇒P=Avρgh, given, A=πr^2=π10-2^2 m^2, v=10 m s^(-1), ρ=1000 kg m^(-3) & h=3 m ⇒P=Avρgh=π10^(-4)×10×1000×10×3=30π W

Water is pumped steadily out of a flooded basement, at the speed of $10 m s^{- 1}$ through a hose (tube) of radius, $1 cm,$ passing through a window, $3 m$ above the water level. The power of the pump is (Assume $g = 10 m s^{- 2}$ , density of water $= 1000 kg m^{- 3}$ )

Solution

Relevant Questions

Water is pumped steadily out of a flooded basement, at the speed of 10 m s-1 through a hose (tube) of radius, 1 cm, passing through a window, 3 m above the water level. The power of the pump is (Assume g=10 m s-2, density of water =1000 kg m-3)

Solution

Relevant Questions

Water is pumped steadily out of a flooded basement, at the speed of $10 m s^{- 1}$ through a hose (tube) of radius, $1 cm,$ passing through a window, $3 m$ above the water level. The power of the pump is (Assume $g = 10 m s^{- 2}$ , density of water $= 1000 kg m^{- 3}$ )