Q69 / 90 · JEE Main 2021 (27 Aug Shift 2) · Physics

Water drops are falling from a nozzle of a shower onto the floor from a height of 9.8 m. The drops fall at a regular interval of time. When the first drop strikes the floor, at that instant, the third drop begins to fall. Locate the position of second drop from the floor when the first drop strikes the floor.

  • A
    2.94 m
  • B
    4.18 m
  • C
    2.45 m
  • Correct answer
    D
    7.35 m

Solution

Figure

For first drop.

h=12g(2n)2

For 2nd  drop

h'=12g(n)2

hh'=41

h'=h4=9.84

so height of 2nd  drop

H=h-h'=9.8-9.84=34×9.8=7.35 m

Hence, the correct answer is option: 'D'.

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