Q2 / 69 · JEE Advanced 2011 (Paper 1) · Chemistry
$\mathrm{AgNO}_3(a q)$ was added to an aqueous $\mathrm{KCl}$ solution gradually and the conductivity of the solution was measured. The plot of conductance $(\Lambda)$ versus the volume of $\mathrm{AgNO}_3$ is


- A$P$
- B$Q$
- C$R$
- Correct answerD$S$
Solution
As $\mathrm{AgNO}_3$ is added to solution, $\mathrm{KCl}$ will be displaced accrding to following reaction
$$
\mathrm{AgNO}_3(a q)+\mathrm{KCl}(a q) \longrightarrow \operatorname{AgCl}(s)+\mathrm{KNO}_3(a q)
$$
For every mole of $\mathrm{KCl}$ displaced from solution, one mole of $\mathrm{KNO}_3$ comes in solution resulting in almost constant conductivity. As the end point is reached, added $\mathrm{AgNO}_3$ remain in solution increasing ionic concentration, hence conductivity increases.
Hence, the correct answer is option: 'D'.