Q34 / 92 · NTA Abhyas (NEET) 2020 · Chemistry · Redox Reactions

Volume of 0.1 M $K_{2} C r_{2} O_{7}$ required to oxidize 35 ml of 0.5 M $F e S O_{4}$ solution is

Correct answer
A
29.2 ml
B
145 ml
C
175 ml
D
58.9 ml

Solution

K_{2} C r_{2} O_{7} + 6 F e S O_{4} + 7 H_{2} S O_{4} \to K_{2} S O_{4} + C r_{2} (S O_{4})_{3} + 3 F e_{2} (S O_{4})_{3} + 7 H_{2} O

For

K_{2} C r_{2} O_{7}, M = 0.1 M, n_{1} = 1, V_{1} = ?

For

F e S O_{4}, M = 0.5 M, n_{2} = 6, V_{2} = 35

ml

\frac{M_{1} V_{1}}{n_{1}} = \frac{M_{2} n_{2}}{n_{2}}

V_{1} = 29.2

ml

Hence, the correct answer is option: 'A'.

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