Q1 / 160 · AP EAMCET 2023 (15 May Shift 1) · Chemistry

Vijayawada FM radio station broadcasts at frequency of 103.4 MHz. The wavelength of the corresponding radio waves (in $\mathrm{m}$ ) is

  • Correct answer
    A
    2.90
  • B
    29.0
  • C
    9.20
  • D
    92.0

Solution

$\lambda=\frac{\mathrm{c}}{\mathrm{v}}=\frac{3 \times 10^8 \mathrm{~ms}^{-1}}{1.034 \times 10^8 \mathrm{~s}^{-1}} \cong 2.90 \mathrm{~m}$

Hence, the correct answer is option: 'A'.

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