Q25 / 125 · BITSAT 2013 · Chemistry

Velocity constant of a reaction at $290 \mathrm{~K}$ was found to be $3.2 \times 10^{-3}$. At $300 \mathrm{~K}$ it will be

  • A
    $1.28 \times 10^{-2}$
  • B
    $9.6 \times 10^{-3}$
  • Correct answer
    C
    $6.4 \times 10^{-3}$
  • D
    $3.2 \times 10^{-4}$

Solution

The velocity constant doubles for every $10^{\circ} \mathrm{C}$ rise in temperature.

Hence, the correct answer is option: 'C'.

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