Q68 / 160 · TS EAMCET 2019 (03 May Shift 2) · Mathematics

Vectors a→, b→, c→, d→ are such that (a→×b→)×(c→×d→)=0→. P1 and P2 are two planes determined by vectors a¯, b¯ and c¯, d¯, respectively. Then the angle between the planes P1 and P2 is

  • Correct answer
    A
    0
  • B
    π4
  • C
    π3
  • D
    π2

Solution

Let, N1→ and N2→ are the normals of planes P1 and P2, respectively.

∴a→×b→=N1→ & c→×d→=N2→

Given, a→×b→×c→×d→=0→

⇒N2→×N2→=0

Hence, the angle between the planes P1 and P2 is zero.

Hence, the correct answer is option: 'A'.

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