Q11 / 73 · NTA Abhyas (JEE Main) 2020 · Chemistry · Some Basic Concepts of Chemistry

V1mL of NaOH of molarity X and V2mL of Ba(OH)2 of molarity Y are mixed together. The mixture is completely neutralized by 100 mL of 0.1N HCl. If V1/V2=1/4 and X/Y = 4 then what fraction of acid is neutralized by Ba(OH)2

  • A
    0.5
  • B
    0.25
  • C
    0.33
  • Correct answer
    D
    0.67

Solution

Meq. of NaOH + Meq. of Ba(OH)2=Meq. of HCl
X.V1+2Y.V2=100×0.1=10
or 4Y.V24+2Y.V2=10
or 3YV2=10
2Y.V2=10×23=6.66
Fraction used by Ba(OH)2=6.6610=0.67

Hence, the correct answer is option: 'D'.

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