Q65 / 75 · JEE Main 2020 (03 Sep Shift 1) · Physics

Using screw gauge of pitch 0.1cm and 50 divisions on its circular scale, the thickness of an object is measured. It should correctly be recorded as,

  • A
    2.121cm
  • Correct answer
    B
    2.124cm
  • C
    2.125cm
  • D
    2.123cm

Solution

Thickness = M.S. Reading + Circular Scale Reading (L.C.)

Here least count is 0.002 cm per division.

From all the four options, the second answer is divisible by this least count. Hence option 2 is correct.

Hence, the correct answer is option: 'B'.

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