$\int\left(\frac{1}{x^2}+\frac{\sin ^3 x+\cos ^3 x}{\sin ^2 x \cos ^2 x}\right) d x=$

• Correct answer
  A

  $\frac{(\sin x-\cos x) x-\sin x \cos x}{x \sin x \cos x}+\mathrm{c}$
• B

  $-\frac{1}{x}+\frac{\sin x+\cos x}{\cos x-\sin x}+c$
• C

  $-\frac{1}{x}+\frac{\sin x-\cos x}{\sin ^2 x \cos ^2 x}+\mathrm{c}$
• D

  $\frac{(\sin x-\cos x) x-\sin x-\cos x}{x(\sin x+\cos x)}+\mathrm{c}$

Hence, the correct answer is option: 'A'.