Q117 / 160 · TS EAMCET 2025 (02 May Shift 1) · Mathematics
$\int_0^{\pi / 4} x^2 \sin 2 x d x=$
- A$\frac{\pi^2-2}{8}$
- B$\frac{\pi(\pi-2)}{8}$
- Correct answerC$\frac{\pi-2}{8}$
- D$\frac{\pi+2}{8}$
Hence, the correct answer is option: 'C'.