$\int e^{4 x}(\sin 3 x-\cos 3 x) d x=$

• A

  $\frac{e^{4 x}}{25}(7 \sin 3 x-\cos 3 x)+\mathrm{c}$
• Correct answer
  B

  $\frac{e^{4 x}}{25}(\sin 3 x-7 \cos 3 x)+\mathrm{c}$
• C

  $\frac{e^{4 x}}{5}(7 \sin 3 x+\cos 3 x)+c$
• D

  $\frac{e^{4 x}}{5}(\sin 3 x+7 \cos 3 x)+c$

Hence, the correct answer is option: 'B'.