$\operatorname{Tanh}^{-1}\left(\frac{1}{3}\right)+\operatorname{Coth}^{-1}(3)=$

• A

  $\operatorname{Sech}^{-1}\left(\frac{1}{3}\right)$
• B

  $\operatorname{Cosech}^{-1}\left(\frac{1}{3}\right)$
• C

  $\operatorname{Cosh}^{-1}\left(\frac{4}{3}\right)$
• Correct answer
  D

  $\operatorname{Sinh}^{-1}\left(\frac{3}{4}\right)$

Hence, the correct answer is option: 'D'.