$\lim _{x \rightarrow \infty}\left(\sqrt[3]{x^3+4 x^2}-\sqrt{x^2-3 x}\right)=$

• Correct answer
  A

  $\frac{17}{6}$
• B

  $\frac{25}{6}$
• C

  $-\frac{1}{6}$
• D

  $\frac{37}{6}$

Hence, the correct answer is option: 'A'.