$\lim _{x \rightarrow 0} \frac{x \tan 2 x-2 x \tan x}{(1-\cos 2 x)^2}=$

• A

  $-\frac{1}{2}$
• Correct answer
  B

  $\frac{1}{2}$
• C

  $\frac{1}{4}$
• D

  $1$

Hence, the correct answer is option: 'B'.