$\begin{aligned} &\text { At } \mathrm{T}(\mathrm{~K}) \text {, the following equation is obtained for a first order reaction. }\\ &\log \frac{\mathrm{k}}{\mathrm{~A}}=-\frac{x}{\mathrm{~T}} \end{aligned}$ $\text { The activation energy for this reaction is equal to ( } R=\text { gas constant) }$

• Correct answer
  A

  $2.303$ $x \mathrm{R}$
• B

  $\frac{2.303 \mathrm{R}}{x}$
• C

  $\frac{x}{2.303 \mathrm{R}}$
• D

  $\frac{1}{2.303 x \mathrm{R}}$

Hence, the correct answer is option: 'A'.