Q60 / 160 · AP EAMCET 2025 (21 MAY SHIFT 2) · Mathematics
$\frac{1}{\sin 1^{\circ} \sin 2^{\circ}}+\frac{1}{\sin 2^{\circ} \sin 3^{\circ}}+\frac{1}{\sin 3^{\circ} \sin 4^{\circ}}+\ldots+\frac{1}{\sin 89^{\circ} \sin 90^{\circ}}=$
- A$\frac{\sin 1^{\circ}}{\tan 1^{\circ}}$
- B$\frac{1}{\sin ^2 1^{\circ}}$
- Correct answerC$\frac{\cot 1^{\circ}}{\sin 1^{\circ}}$
- D$\frac{\tan 1^{\circ}}{\cos 1^{\circ}}$
Hence, the correct answer is option: 'C'.